IB CHEMISTRY

2.1.1

Ion Formation

1. The Octet Rule & Energetic Stability

Atoms react to minimize their potential energy. This is typically achieved by attaining the electron configuration of the nearestNoble Gas (a full valence shell).

Interactive: Formation of a Sodium Cation (Na⁺)

Observe how losing the valence electron affects the size of the particle.

Valence e⁻
Na
Na Atom (Radius: 186 pm)

Cations (Positive)

Formed by metals (Low Ionization Energy).

They lose valence electrons.

Na [2,8,1] → Na⁺ [2,8] + e⁻

Anions (Negative)

Formed by non-metals (High Electron Affinity).

They gain valence electrons.

Cl [2,8,7] + e⁻ → Cl⁻ [2,8,8]

2. Isoelectronic Species

Definition for Paper 1:

Different chemical species that possess the exact same electron configuration but distinct nuclear charges.

The Trend: Radius Decreases with Nuclear Charge

As the number of protons (Nuclear Charge, \(Z\)) increases across an isoelectronic series, the ionic radius decreases.

  • Why? The number of electron shells is constant (same shielding).
  • The increasing positive charge from the nucleus pulls the valence shell closer.

Comparing Isoelectronic Radii (The Neon Series)

Paper 2 Style
Rank the following species in order of DECREASING size:
\( N^{3-}, Mg^{2+}, F^-, Na^+, O^{2-} \)

3. Transition Metal Nuance

⚠️ CRITICAL EXAM TIP: 4s vs 3d

"First In, First Out" Rule: When writing the configuration for a transition metal ION, always remove the 4s electrons completely before touching the 3d electrons.

Neutral Fe Atom[Ar] 4s² 3d⁶
Fe²⁺ Ion (Lose 4s)[Ar] 3d⁶

NOT [Ar] 4s² 3d⁴

Fe³⁺ Ion (Stable)[Ar] 3d⁵

Half-filled d-subshell is extra stable.

4. Required Polyatomic Ions

NameFormulaChargeNote
AmmoniumNH₄⁺+1Only common polyatomic cation
HydroxideOH⁻-1Base former
NitrateNO₃⁻-1"Ate" = More Oxygen
SulfateSO₄²⁻-2Sulfuric acid salt

Student Practice Set

1.
Which series is arranged in order of decreasing ionic radius?
2.
What is the correct electron configuration for the Fe²⁺ ion?