IB CHEMISTRY

Structure 2.3: Exam Practice

Test your understanding of Metallic Bonding and Alloys.

Part A: Multiple Choice (Mock)

Key Concepts Tested in Paper 1

  • Definition: Identifying the description "electrostatic attraction between lattice of cations and delocalized electrons".
  • Trends: Predicting that Al > Mg > Na > K for melting point.
  • Conductivity: Identifying that functionality relies on mobile electrons, not ions.

Full interactive MCQs coming in future update.

Part B: Structured Questions (Paper 2)

Question 1 Same Period Trend

Explain why Aluminum has a higher melting point than Sodium. (3 marks)

Mark Scheme:

  • Aluminum has a higher charge (+3) than Sodium (+1).
  • Aluminum contributes more delocalized electrons (3 vs 1) to the "sea".
  • Aluminum has a smaller ionic radius.
  • Therefore: Stronger electrostatic attraction between cations and delocalized electrons.

Question 2 Properties

Explain, with reference to structure and bonding, why metals are malleable whereas ionic compounds are brittle. (4 marks)

Mark Scheme:

  • Metals: Non-directional bonding / "Sea" of electrons moves with the cations.
  • Layers of cations can slide over each other without breaking the bond.
  • Ionic: Directional electrostatic attraction between fixed ions.
  • Sliding layers brings ions of like charge (+/+) together, causing repulsion and shattering.
HL Only

Question 4 Transition Metals

Compare the bonding strength of Calcium and Titanium. Justify your answer. (3 marks)

Mark Scheme:

  • Titanium has a stronger metallic bond.
  • Titanium is a transition metal and delocalizes both 4s and 3d electrons.
  • Calcium only delocalizes 4s electrons (fewer delocalized electrons per atom).